if i put my x pipe on w/o the mil elimantors will my car still run fine? just with a check engine light?
The computer uses the oxygen sensor input to regulate the fuel mixture, which is referred to as the fuel "feedback control loop." The computer takes its cues from the O2 sensor and responds by changing the fuel mixture. This produces a corresponding change in the O2 sensor reading. This is referred to as "closed loop" operation because the computer is using the O2 sensor's input to regulate the fuel mixture. The result is a constant flip-flop back and forth from rich to lean which allows the catalytic converter to operate at peak efficiency while keeping the average overall fuel mixture in proper balance to minimize emissions. It is a complicated setup but it works.
That is correct for the FRONT set of o2's. MILS are used in the rear set which ONLY measures the output after the cat to see if the cats are working or not. They have zero control over a/f. The fronts do ALL of that.
The computer uses the oxygen sensor input to regulate the fuel mixture, which is referred to as the fuel "feedback control loop." The computer takes its cues from the O2 sensor and responds by changing the fuel mixture. This produces a corresponding change in the O2 sensor reading. This is referred to as "closed loop" operation because the computer is using the O2 sensor's input to regulate the fuel mixture. The result is a constant flip-flop back and forth from rich to lean which allows the catalytic converter to operate at peak efficiency while keeping the average overall fuel mixture in proper balance to minimize emissions. It is a complicated setup but it works.
wow stangman thats a lot of typing when the answer you gave only sounds rite when you say it fast
the rear o2 sensors measure the heat difference from the front 2 to the rear 2. if the differenceist to high the computer sends a code. if the difference is to low or the same the computer sends a code. the mil elims, are simply a signal reducer, the signal i think is only a .5 volts of difference. i think, if im wrong please some one correct me.
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