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OT: Any Math people in here?

  • Thread starter Thread starter timwcol2
  • Start date Start date Nov 24, 2006

timwcol2

New Member
May 4, 2006
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Nov 24, 2006
#1
  • Nov 24, 2006
  • #1
I need help with these four questions..if possible can you work the equation all the way so i will have an example to study and reference.

http://i81.photobucket.com/albums/j216/timwcol29/help.jpg
 
8

86bluecobra

Advanced Member
Dec 20, 2004
4,265
12
69
B.C. Canada
Nov 24, 2006
#2
  • Nov 24, 2006
  • #2
oh geez it has been 2 long. if i had my old math tex book maybe.
 

2nd Mustang

Founding Member
Feb 24, 2002
2,488
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46
Southern California
Nov 24, 2006
#3
  • Nov 24, 2006
  • #3
Sorry, it's been too long ago. This kind of math is not used in my simple life. I just need to add and subtract to balance my checkbook.

My son could probably do it, a chemist by major, but he's too busy saving the world, one video game at a time. Good luck.
 

timwcol2

New Member
May 4, 2006
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Nov 25, 2006
#4
  • Nov 25, 2006
  • #4
i dont remeber hardly anything from high school...
 

3-0-II

Member
Oct 24, 2006
110
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17
Redwood City, CA
Nov 25, 2006
#5
  • Nov 25, 2006
  • #5
If I wasn't so fed up with my own math problems (HA PUN!!!!) I'd offer to try and help out.

But man am I ever toast. What math are you in?
 

bad68coupe

New Member
Jul 18, 2006
220
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Richardson, TX
Nov 25, 2006
#6
  • Nov 25, 2006
  • #6
what level math is this. if you simply need to multiply them, then it is not that tough, but if it is calculus or something that is a different case
 
B

blue65coupe

New Member
Aug 14, 2006
71
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North Carolina
Nov 25, 2006
#7
  • Nov 25, 2006
  • #7
Peaked my interest then realized I'm too old. I'd just math it out and not reduce. I do remember taking out the numbers if divisible.

2a(sq)m-8b(sq)m/ax+2bx

then you can remove like symbols but I don't remember how they have to coincide. I think they have to be through the whole equation like the numbers but maybe not.

I'm going back to my wheels. I know what a 100lbs of torque is.

Ooh--[2a(sq)-8b(sq)]m/[a+2b]x There is your answer...I think
 

Taranis

New Member
Nov 12, 2004
92
1
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Austin, Texas
Nov 25, 2006
#8
  • Nov 25, 2006
  • #8
You're trying to solve for X in terms of the other variables, or are trying to solve for every variable?
 
B

blue65coupe

New Member
Aug 14, 2006
71
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North Carolina
Nov 25, 2006
#9
  • Nov 25, 2006
  • #9
I don't think he's trying to solve for any variable. Just lowest terms--simplify equation. If it were me, I'd go to a math forum. Most of us stop at figuring compression ratios and rpms at a given speed.
 

jikelly

20+ Year Stangneter
Jul 9, 2003
872
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Lubbock Tx
Nov 25, 2006
#10
  • Nov 25, 2006
  • #10
I hope to teach this crap to kids someday so I figured I give this problem a try.

I think all we want to do is pull out common factors and reduce the fraction so the terms in the top part...

8*a^2*m - 32*b^2*m

have 8 and m in common. We can pull those out to rewrite it as...

(a^2 - 4*b^2)*(8*m)

The terms have nothing else in common so that's it for the top. Now for the bottom...

4*a*x + 8*b*x

Okay so in the bottom part we can see that the terms have 4 and x in common (4 and x are multiplied with both a and 2*b) so let's pull those out.

(a + 2*b)*(4*x)

So our fraction (it's not an equation because they haven't given us an = sign) becomes...

(a^2 - 4*b^2)*(8*m)
---------------------
(a + 2*b)*(4*x)

This is where the crappy part comes in. If you look at the terms on top and on bottom there is something they have in common (we can divide things into other things). It's real easy to see that we can divide 8 by 4 to get...


(a^2 - 4*b^2)*(2*m)
---------------------
(a + 2*b)*x

But we can also do something with (a + 2*b). It will divide into (a^2 - 4*b^2) if we factor (rewrite) the top into (a + 2*b)*(a-2*b). If you use "foil" on it you'll see that...

(a + 2*b)*(a - 2*b) becomes a^2 + 2*a*b - 2*a*b - 4*b^2 which is a^2 - 4*b^2

That's the crappy part, not so much the foil thing, but seeing that (a^2 - 4*b^2) can be factored.

Okay so now if we factor and rewrite our fraction we see...

[(a + 2*b)*(a - 2*b)]*(2*m)
----------------------------
(a + 2*b)*x

So you can see that the (a + 2*b) can divide into the top, I like to say that it cancels out since it is on both top and bottom. and our fraction becomes...

(a - 2*b)*(2*m)
----------------
x

Smooth huh? No it sucks I'm not going to lie to you, but it's math and it is an important tool that can be used to solve a lot of problems (like figuring out how far you can go on a tank of gas, or your suspension geometry). Learn it and you be ahead of so many others that can't do it. A TI 89 will solve these type problems symbolically. It is an awesome tool that really helps with the algebra crap. Don't go to engineering school without it.

That help?
 
B

bnickel

Founding Member
Aug 21, 2002
5,640
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77
lubbock, texas
Nov 25, 2006
#11
  • Nov 25, 2006
  • #11
i don't unserstand how you guys can understand that crap at all. i failed algebra every time i took it, even in college. had to take the "comsumer" math courses in place of them. the only algebraic equation i was ever to able to use and make it work was for figuring out the acoustics of a given room (sound tech major) math was the one subject in school that i absolutely hated, well just algebra really. most stuff i can figure in my head but this crap puts my brain in a coma!!!!! maybe that's why i spend most of my time on online forums now. LOL. seriously, the better you can get at this stuff the better off you'll be in life later down the road.
 
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blue65coupe

New Member
Aug 14, 2006
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North Carolina
Nov 25, 2006
#12
  • Nov 25, 2006
  • #12
Maybe it's been too long but you can't independently break down the top and bottom can you? That changes the whole fraction. Top and bottom have to have same properties to cancel out


I'm out...been too long
 

timwcol2

New Member
May 4, 2006
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Nov 25, 2006
#13
  • Nov 25, 2006
  • #13
i guess its just reg. algebra. Im taking an online school through my work so I can get a better job...I wont use any of this stuff in the job i want because we have computer programs for the job that does everything..the course is for an ass.in electrical engineering tech.
 

jikelly

20+ Year Stangneter
Jul 9, 2003
872
53
99
Lubbock Tx
Nov 25, 2006
#14
  • Nov 25, 2006
  • #14
Here are the solutions for the third and forth problem.

I hope you can read this.


Good luck with it. Man it looks like he's a hard #$$ from these problems. I always hated it when my teachers would take a simple concept and twist it up with a bunch of others and then call that a fair test of your knowledge.
 

jikelly

20+ Year Stangneter
Jul 9, 2003
872
53
99
Lubbock Tx
Nov 25, 2006
#15
  • Nov 25, 2006
  • #15
blue65coupe said:
Maybe it's been too long but you can't independently break down the top and bottom can you? That changes the whole fraction. Top and bottom have to have same properties to cancel out


I'm out...been too long
Click to expand...

Yes you can. It's alright as long as you don't take anything away from the top.

8/7 can be rewritten as (3 + 5)/7, or (5 + 3)/7
 

timwcol2

New Member
May 4, 2006
35
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Nov 25, 2006
#16
  • Nov 25, 2006
  • #16
thanks for the help..hope i dont have to do this stuff anymore,it sucks
 

Taranis

New Member
Nov 12, 2004
92
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Austin, Texas
Dec 2, 2006
#17
  • Dec 2, 2006
  • #17
I took Calculus II in college and was wondering " Where am I EVER going to need this?"
Then I took Physical Chamistry and Thermodynamics. I wished I had listened....
 
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