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Trig help again...

  • Thread starter Thread starter 1105
  • Start date Start date May 4, 2005

1105

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#1
  • May 4, 2005
  • #1
Find the indicated power using DeMoivre's Theorem.

(sqrt(3)-i)^10

ans in trig form

ans in simplified standard form (A + Bi)


Find the fourth roots of 81i. Ans's in trig form
 

1105

I AM the random post master...bow down
May 3, 2003
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May 4, 2005
#2
  • May 4, 2005
  • #2
anyone?
 

BlackVert

15 Year Member
Oct 3, 2003
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May 4, 2005
#3
  • May 4, 2005
  • #3
sorry, too long ago for me ...
 

davins130

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May 21, 2004
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#4
  • May 4, 2005
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when will that ever help you in life? i hope i dont have to take that class anytime soon
 
N

Nagash01WS6

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Apr 15, 2003
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Deland, FL
May 5, 2005
#5
  • May 5, 2005
  • #5
1105 said:
Find the indicated power using DeMoivre's Theorem.

(sqrt(3)-i)^10

ans in trig form

ans in simplified standard form (A + Bi)


Find the fourth roots of 81i. Ans's in trig form
Click to expand...

hope im not too late... i know you have your final tomorrow / today.

Anyway... DeMoivres theroem...

(sqrt(3)-i)^10
tan(y/x) = tan(-1/sqrt(3)) = 11pi/6
sqrt(3)^2+(-1)^2=4
4*10(cos((11pi/6)*10) + isin((11pi/6)*10))

If I remember correctly that should work.

I think simplifying refines it to....
40(cos(55pi/3) + isin(55pi/3))

Then use your calc to figure cos and sin and thats your simplified.
 

1105

I AM the random post master...bow down
May 3, 2003
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Daytona Bch, FL
May 5, 2005
#6
  • May 5, 2005
  • #6
sqrt(3)^2+(-1)^2=4
Click to expand...

sqrt of that should be the sqrt of 10...

3^2 = 9, (-1)^2 = 1 added together = 10

Just had to change the coef infront of the cos + isin to 10sqrt10 right?

again, thanks for the help
 

94GTLaserRC

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15 Year Member
May 7, 2002
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Ernan Says "here it comes... dushbag"
May 5, 2005
#7
  • May 5, 2005
  • #7
Just multiply BOTH sides of the equation by ZERO, and everything cancels out.
RC
 

1105

I AM the random post master...bow down
May 3, 2003
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Daytona Bch, FL
May 5, 2005
#8
  • May 5, 2005
  • #8
How did you make it out of college RC?

Finally done with that class! I think I did good on the final. There were some I wasnt sure about, others were so easy it wasnt funny...

here's one, anyone can figure it out... Guy is flying a kyte with a 500ft string at an angle of elevation of 60*. How high is the kyte off the ground?

1. 577 feet, 2. 500 feet, 3. 430 feet? I love thoes questions
 

BlackVert

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Oct 3, 2003
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Bethesda, MD
May 5, 2005
#9
  • May 5, 2005
  • #9
1105 said:
How did you make it out of college RC?

Finally done with that class! I think I did good on the final. There were some I wasnt sure about, others were so easy it wasnt funny...

here's one, anyone can figure it out... Guy is flying a kyte with a 500ft string at an angle of elevation of 60*. How high is the kyte off the ground?

1. 577 feet, 2. 500 feet, 3. 430 feet? I love thoes questions
Click to expand...
that one's easy ... 447 feet (if he is using all 500 feet of the string)
 

1105

I AM the random post master...bow down
May 3, 2003
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May 5, 2005
#10
  • May 5, 2005
  • #10
BlackVert said:
that one's easy ... 447 feet (if he is using all 500 feet of the string)
Click to expand...
even if he was using all of it... the kyte would have to be right above him to be 500feet in the air, which would be 90* of elevation, and he would have to be standing on top of a roof to have it up to 577 feet
 

BlackVert

15 Year Member
Oct 3, 2003
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May 5, 2005
#11
  • May 5, 2005
  • #11
 

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BlackVert

15 Year Member
Oct 3, 2003
5,589
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98
Bethesda, MD
May 5, 2005
#12
  • May 5, 2005
  • #12
1105 said:
even if he was using all of it... the kyte would have to be right above him to be 500feet in the air, which would be 90* of elevation, and he would have to be standing on top of a roof to have it up to 577 feet
Click to expand...
yeah, but it is not 430 feet, it is 447 feet, unless the string is curved ... ugh
 
N

Nagash01WS6

New Member
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Deland, FL
May 6, 2005
#13
  • May 6, 2005
  • #13
heh... angle of elevation... would be from the guy on the ground to the kite... so the kite is at a 60 degree angle from him.

If he is using 500 ft of string... then...

sin(x/500) = 60

since opposite is sin, and the vertical distance of the kite from the ground.

to solve...

arcsin(60) = x/500
x=433ft
 

donjohn

New Member
Feb 7, 2004
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Irvine - Southern California
May 6, 2005
#14
  • May 6, 2005
  • #14
1105 said:
How did you make it out of college RC?

Finally done with that class! I think I did good on the final. There were some I wasnt sure about, others were so easy it wasnt funny...

here's one, anyone can figure it out... Guy is flying a kyte with a 500ft string at an angle of elevation of 60*. How high is the kyte off the ground?

1. 577 feet, 2. 500 feet, 3. 430 feet? I love thoes questions
Click to expand...

that's a funny question... promotes you to think logically i guess, i probably would have done the calculation anyways, just to make sure the teacher didn't screw up

on my engineering midterm the other day, a bunch of people were asking him questions, so the dumb guys says "ok, all your questions are straightforward, any other dumb questions and you automatically get -2 points, for a good question +1" -i thought that was pretty hilarious
 
D

DARK-5.0

Founding Member
Feb 20, 2002
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Leawood, KS
May 6, 2005
#15
  • May 6, 2005
  • #15
sorry bud, all i learned today in class was noise diagnosing and some leak down tests. it was kinda boring

Jeremy
 

94GTLaserRC

Squint as you approach, lest you be blinded by my
15 Year Member
May 7, 2002
11,178
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Ernan Says "here it comes... dushbag"
May 6, 2005
#16
  • May 6, 2005
  • #16
How about this one:

How many cubic YARDS of dirt are in a hole 3ft x 3ft x 3ft?

RC
 

BlackVert

15 Year Member
Oct 3, 2003
5,589
9
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Bethesda, MD
May 6, 2005
#17
  • May 6, 2005
  • #17
um ... the hole is empty ... lol
 

1105

I AM the random post master...bow down
May 3, 2003
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Daytona Bch, FL
May 6, 2005
#18
  • May 6, 2005
  • #18
yea.. none...

I forgot the exact answers for the problem, but 2 were defently not the answer and you could tell just by looking at it... The other answer was 400 something
 
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