Look at the relay diagram. The two step will have its black wire permanently grounded at all times. The red 12v wire on the two step will get its 12v from pin# 87 on the relay. Pin# 87 is getting its power from pin# 30. However, when the relay is open (not activated) the connection between pin# 87 and pin# 30 is broken.
In order to close the gap between pin# 87 and pin# 30, a 12v current has to travel between pins# 85 & 86. If you wire pin# 86 to your grounded clutch switch, then pressing the clutch to the floor will ground pin# 86. You would then press the momentary switch, which is connected to a permanent 12v source. This allows current to flow from pin# 85 to pin# 86, which in effect, closes the connection between pins# 87 & 30, which allows 12v to run through the red 12v wire of the 2 step.
Once power is established between pins# 87 & 30, the jumper wire runs power back to pin# 85, which keeps the relay activated, without you having to hold the momentary switch on. Once you release the clutch pedal, the ground to pin# 86 is broken, which opens the relay, causing 12v to be lost to the 2 step, thus turning it off.
When I first started messing with relays, it confused the living daylights out of me. They are a pretty neat little device though. I hope this helps clarify things a little. If not, the diagram does work. I attached my modified version for the line lock as well. I added a separate switch so I could use the line lock by itself, and also installed a diode to prevent 12v from feeding back and keeping it activated.
Good luck!
Joe