whats your take on a saleen series supercharger???

Roush21 said:
The roots type "saleen" or "kb" will make more tq and not alot more of hp, the centri supercharger "vortech" will make more hp and not alot more of tq. Roots type is instant but the curve wont climb as high as a centri...so once you get to like 5K a centri car will blow right by a roots because its still climbing in boost and hp. ANd about the comment on the noisiness of the vortech just get the SQ version its much quieter than ANY roots blower out there.
Bro, the Kenne Bell is in no way a "Roots" type blower. Go to KB's website or anyone else on these forums that are running the kit and you will plainly see that a KB blower has full boost at 2000rpm and still climbs all the way to redline, just like a Centrifugal. The curve is just flatter, but in no way drops off. Do you research before you start bashing other types of blowers. And to address the "quiet" issues, you would never know that a person had a KB unless he or she popped their hood.
 
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nuff said..........
 
hehe

I raced a car with a vortech from a roll.. I instantly pull cars on him cuzz im always in the power band.. and I had enough of a lead to stay ahead.. he also had a lot more power then me..
 
run him from a dead stop and see what happens , or run him from a roll but at the middle of his rpm range that way he will be into boost sooner , then post results of that , it would be interesting to see the outcome
 
mattch2 said:
so if the vortech and the saleen blowers were in a race to the end of the quarter would the votech catch him by the end?.. I know its a pathetic explanation but i just want to see how long a saleen blower will keep goign before it dies..lol

With a crappy 60' (2.666 for instance) I can trap at 108 MPH.. that was last year with a few problems. I havent raced since I fixed them, but after all the fixes I gained 7 HP and 14 tq, so Im assuming I could go even faster
 
I just bought the Saleen Series II Supercharger. I am getting it installed the week of the 15th. Here is why I bought it: 1) I Got an amazing Deal on it. 2) I personally like a roots type better because of the broader powerband. 3) TORQUE! 4) I got an amazing deal on it.

Personally i think it is in the eyes of the beholder. People love their Saleens, people love their Kenny Belle's, people love their vortecs. I personally think that Kenny Belle is the best way to go but i dont have that kind of money. There is one other thing though...I hear enough of bashing from LS1 guys and from imports, we dont need to hear it from people on this site. He just wanted opinions. Not bashings.
 
WRXracer-out of the box, the Saleen is WEAK, no offense, but look at your numbers...(not taking a stab at you or your car;i know how you got it and i wouldve taken it too)
but if you are going to buy a blower all in the 4-5k price range, a centri blower with an intercooler, or a kenne bell is the only way to go.

it doesnt matter how pretty of a torque curve you have because down low, torque doesnt add up to much horsepower under 3500 anyways, and horsepower is what wins races.
 
just some guy said:
WRXracer-out of the box, the Saleen is WEAK, no offense, but look at your numbers...(not taking a stab at you or your car;i know how you got it and i wouldve taken it too)
but if you are going to buy a blower all in the 4-5k price range, a centri blower with an intercooler, or a kenne bell is the only way to go.

it doesnt matter how pretty of a torque curve you have because down low, torque doesnt add up to much horsepower under 3500 anyways, and horsepower is what wins races.
Nicely said, but I would also have to add that you can't make big HP #'s without lots of torque!!!
 
Torque / Horsepower relation

Have you ever looked at the specs of an engine in a magazine and seen something like "this engine makes 300 pound-feet of torque at 4,000 RPM," and wondered how much power that was? How much horsepower are we talking about here? You can calculate how many foot-pounds of horsepower this engine produces using a common equation:

(Torque x Engine speed) / 5,252 = Horsepower

The engine that makes 300 pound-feet of torque at 4,000 RPM produces [(300 x 4,000) / 5,252] 228 horsepower at 4,000 RPM. But where does the number 5,252 come from?

To get from pound-feet of torque to horsepower, you need to go through a few conversions. The number 5,252 is the result of lumping several different conversion factors together into one number.

First, 1 horsepower is defined as 550 foot-pounds per second . The units of torque are pound-feet. So to get from torque to horsepower, you need the "per second" term. You get that by multiplying the torque by the engine speed.

But engine speed is normally referred to in revolutions per minute (RPM). Since we want a "per second," we need to convert RPMs to "something per second." The seconds are easy -- we just divide by 60 to get from minutes to seconds. Now what we need is a dimensionless unit for revolutions: a radian. A radian is actually a ratio of the length of an arc divided by the length of a radius, so the units of length cancel out and you're left with a dimensionless measure.

You can think of a revolution as a measurement of an angle. One revolution is 360 degrees of a circle. Since the circumference of a circle is (2 x pi x radius), there are 2-pi radians in a revolution. To convert revolutions per minute to radians per second, you multiply RPM by (2-pi/60), which equals 0.10472 radians per second. This gives us the "per second" we need to calculate horsepower.

Let's put this all together. We need to get to horsepower, which is 550 foot-pounds per second, using torque (pound-feet) and engine speed (RPM). If we divide the 550 foot-pounds by the 0.10472 radians per second (engine speed), we get 550/0.10472, which equals 5,252.

So if you multiply torque (in pound-feet) by engine speed (in RPM) and divide the product by 5,252, RPM is converted to "radians per second" and you can get from torque to horsepower -- from "pound-feet" to "foot-pounds per second."
 
Dan_Soprano said:
Have you ever looked at the specs of an engine in a magazine and seen something like "this engine makes 300 pound-feet of torque at 4,000 RPM," and wondered how much power that was? How much horsepower are we talking about here? You can calculate how many foot-pounds of horsepower this engine produces using a common equation:

(Torque x Engine speed) / 5,252 = Horsepower

The engine that makes 300 pound-feet of torque at 4,000 RPM produces [(300 x 4,000) / 5,252] 228 horsepower at 4,000 RPM. But where does the number 5,252 come from?

To get from pound-feet of torque to horsepower, you need to go through a few conversions. The number 5,252 is the result of lumping several different conversion factors together into one number.

First, 1 horsepower is defined as 550 foot-pounds per second . The units of torque are pound-feet. So to get from torque to horsepower, you need the "per second" term. You get that by multiplying the torque by the engine speed.

But engine speed is normally referred to in revolutions per minute (RPM). Since we want a "per second," we need to convert RPMs to "something per second." The seconds are easy -- we just divide by 60 to get from minutes to seconds. Now what we need is a dimensionless unit for revolutions: a radian. A radian is actually a ratio of the length of an arc divided by the length of a radius, so the units of length cancel out and you're left with a dimensionless measure.

You can think of a revolution as a measurement of an angle. One revolution is 360 degrees of a circle. Since the circumference of a circle is (2 x pi x radius), there are 2-pi radians in a revolution. To convert revolutions per minute to radians per second, you multiply RPM by (2-pi/60), which equals 0.10472 radians per second. This gives us the "per second" we need to calculate horsepower.

Let's put this all together. We need to get to horsepower, which is 550 foot-pounds per second, using torque (pound-feet) and engine speed (RPM). If we divide the 550 foot-pounds by the 0.10472 radians per second (engine speed), we get 550/0.10472, which equals 5,252.

So if you multiply torque (in pound-feet) by engine speed (in RPM) and divide the product by 5,252, RPM is converted to "radians per second" and you can get from torque to horsepower -- from "pound-feet" to "foot-pounds per second."
good job...i know all that though, ive got a few semesters left before i get my b.s. in mechanical engineering, and a math minor.

im always the one who has to explain stuff like that to people, i just try not to get into it everywhere, cuz lots of people still dont understand
 
Have you ever looked at the specs of an engine in a magazine and seen something like "this engine makes 300 pound-feet of torque at 4,000 RPM," and wondered how much power that was? How much horsepower are we talking about here? You can calculate how many foot-pounds of horsepower this engine produces using a common equation:

(Torque x Engine speed) / 5,252 = Horsepower

The engine that makes 300 pound-feet of torque at 4,000 RPM produces [(300 x 4,000) / 5,252] 228 horsepower at 4,000 RPM. But where does the number 5,252 come from?

To get from pound-feet of torque to horsepower, you need to go through a few conversions. The number 5,252 is the result of lumping several different conversion factors together into one number.

First, 1 horsepower is defined as 550 foot-pounds per second . The units of torque are pound-feet. So to get from torque to horsepower, you need the "per second" term. You get that by multiplying the torque by the engine speed.

But engine speed is normally referred to in revolutions per minute (RPM). Since we want a "per second," we need to convert RPMs to "something per second." The seconds are easy -- we just divide by 60 to get from minutes to seconds. Now what we need is a dimensionless unit for revolutions: a radian. A radian is actually a ratio of the length of an arc divided by the length of a radius, so the units of length cancel out and you're left with a dimensionless measure.

You can think of a revolution as a measurement of an angle. One revolution is 360 degrees of a circle. Since the circumference of a circle is (2 x pi x radius), there are 2-pi radians in a revolution. To convert revolutions per minute to radians per second, you multiply RPM by (2-pi/60), which equals 0.10472 radians per second. This gives us the "per second" we need to calculate horsepower.

Let's put this all together. We need to get to horsepower, which is 550 foot-pounds per second, using torque (pound-feet) and engine speed (RPM). If we divide the 550 foot-pounds by the 0.10472 radians per second (engine speed), we get 550/0.10472, which equals 5,252.

So if you multiply torque (in pound-feet) by engine speed (in RPM) and divide the product by 5,252, RPM is converted to "radians per second" and you can get from torque to horsepower -- from "pound-feet" to "foot-pounds per second."

I am a Flight Engineer for the US Navy

Whew! Glad you clarified you were an engineer, I was just thinking "Man, that guy can sure copy and paste"! ;)